Thursday, June 28, 2012

Homework #11






C.5 Problems #1-3

1.
a. Nothing would happen to the solution if the beaker remained undisturbed and no more KCl was added. If one crystal of KCl was added the extra solutes would become precipitate, and the solution would rebalance itself.
b. See drawing

2. See drawing

3.
a and b: See drawings.
c. In 3a, the concentration of the solution expressed as a percent KCl by mass is 10%. Since the amount of water is double in 3b, 10g/200g X 100% = 5%. The percent concentration of 3a is 10%, where as the percent concentration of 3b is 5%.

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